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Les commandes principales consistent à positionner la tortue, lever ou baisser le crayon (pour écrire ou non lorsque la tortue se déplace) et à commander les mouvements de la tortue (avancer/reculer, tourner à gauche/droite d'un certain angle).\n\nPour mieux comprendre et découvrir les commandes accessibles, étudier l'exemple de démonstration ci-dessous :"},{"metadata":{"trusted":true},"cell_type":"code","source":"import turtle as tt # import du module turtle dans Basthon\n\ntt.speed(3)         # vitesse moyenne (maxi = 10)\n\ntt.penup()          # lève le crayon (pour ne pas écrire pendant le déplacement)\ntt.setposition(-100, 100) \n# origine (0, 0) au centre du cadre de dessin (dimensions 600x600)\ntt.pendown()        # abaisse le crayon (pour voir la trace de la tortue)\n\ntt.forward(20)      # avance de 20\ntt.left(60)         # virage de 60° vers la gauche\ntt.forward(100)    \ntt.right(120)       # virage de 120° vers la droite\ntt.pencolor(\"red\")  # couleurs autorisées  \"blue\", \"yellow\", \"brown\", \"black\", \"purple\", \"green\"\ntt.forward(100)  \ntt.left(60)       \ntt.forward(100)     # recule de 100\ntt.backward(70)  \ntt.right(90)   \ntt.pencolor(\"green\")  \ntt.forward(300)  \n\ntt.penup()\ntt.home()           # retour à l'origine\n\ntt.done()           # indispensable pour activer la tortue dans Basthon","execution_count":3,"outputs":[{"output_type":"display_data","data":{"image/svg+xml":"<svg xmlns=\"http://www.w3.org/2000/svg\" width=\"640\" height=\"480\" preserveaspectratio=\"xMidYMid meet\" viewbox=\"0 0 640 480\"><animate id=\"af_834c721b65114680add0597f36cbe268_0\" attributename=\"opacity\" attributetype=\"CSS\" from=\"1\" to=\"1\" begin=\"0s\" dur=\"1ms\" fill=\"freeze\"></animate><g transform=\"translate(320 240)\"></g><g transform=\"translate(320 240)\"><line x1=\"0\" y1=\"0\" x2=\"0\" y2=\"0\" style=\"stroke: black;stroke-width: 1\"><animate id=\"af_834c721b65114680add0597f36cbe268_2\" attributename=\"x2\" 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Fractales : courbe de Koch</h2>\n\nLa courbe de Koch est une fractale reposant sur la construction récursive suviante :\n1. Étape 1 : Tracer un segment de longueur a. \n\n![Image de losange](https://githepia.hesge.ch/info_sismondi/3AM.OS/-/raw/main/recursivite/koch_0.png)\n\n2. Étape 2 : Diviser le segment en 3 parties de même longueur. Construire un triangle équilatéral ayant pour base le segment médian de la première étape, et en supprimer la base.\n![Image de losange](https://githepia.hesge.ch/info_sismondi/3AM.OS/-/raw/main/recursivite/koch_1.png)\n\n3. Étape 3 : Reprendre l'étape 2 sur chacun des segments créés.\n![Image de losange](https://githepia.hesge.ch/info_sismondi/3AM.OS/-/raw/main/recursivite/koch_2.png)\n\n4. Et ainsi de suite...\n![Image de losange](https://githepia.hesge.ch/info_sismondi/3AM.OS/-/raw/main/recursivite/koch_3.png)\n"},{"metadata":{},"cell_type":"markdown","source":"On peut construire récursivement cette courbe. \n\nLa fonction de tracer prend deux paramètres en entrée :\n* la longeur $a$ du segment.\n* l'étape $n$ de \"profondeur\" de récursivité. \n\nPar exemple, à la profondeur $n=0$, on trace un simple segment : ceci constituera la condition d'arrêt des appels récursifs. À la profondeur $n=1$, le tracé donne la figure de l'étape 2."},{"metadata":{},"cell_type":"markdown","source":"<h2 class=\"alert alert-warning\">ex 1 : Dessiner avec la tortue (pas de récursivité ici)  la figure correspondant à l'étape 2 (décrite ci-avant).</h2>\nÉcrire une fonction etape2(a) pour réaliser cette tache."},{"metadata":{"trusted":false},"cell_type":"code","source":"tt.speed(10)\n\n\ndef etape2(a):\n    # VOTRE CODE CI-DESSOUS\n    #...\n    \n# test:\na = 50\netape2(a)\n\ntt.done()","execution_count":null,"outputs":[]},{"metadata":{},"cell_type":"markdown","source":"<h2 class=\"alert alert-warning\">ex 2 : Courbe de Koch : fonction récursive.</h2>\n\nEn vous inspirant de la logique du code de la fonction précédente (en la \"rendant récursive\"), écrire une fonction koch(a, n) récursive qui :\n\n- prend comme paramètres un nombre entier a représentant la longueur du segment et un entier n égal au nombre de récursions souhaité.\n- construit la courbe de Koch en divisant récursivement chacun des segments\n\n*Rappel* : si n=0, le tracé est un simplement segment de longueur a."},{"metadata":{"trusted":false},"cell_type":"code","source":"tt.speed(10)\ntt.penup()\ntt.setposition(-300, 0) \ntt.pendown()\n\ndef koch(a, n):\n    # VOTRE CODE CI-DESSOUS\n    #...\n\nkoch(360, 3)\n\ntt.done()","execution_count":null,"outputs":[]},{"metadata":{},"cell_type":"markdown","source":"<h2 class=\"alert alert-info\">Et pour s'amuser encore un peu...</h2>\nExécuter le code ci-dessous :"},{"metadata":{"trusted":false},"cell_type":"code","source":"a = 180\n\ntt.speed(10)\ntt.penup()\ntt.setposition(-a/2, a/3) \ntt.pendown()\n\ndef koch(a, n):\n    if n == 0:\n        tt.forward(a)\n    else:\n        koch(a/3, n-1)\n        tt.left(60)\n        koch(a/3, n-1)\n        tt.right(120)\n        koch(a/3, n-1)\n        tt.left(60)\n        koch(a/3, n-1)\n\ndef flocon(a, n):\n    for i in range(3):\n        koch(a, n)\n        tt.right(120)\n        \nflocon(a, 3)\n\ntt.penup()\ntt.home()\n\ntt.done()","execution_count":null,"outputs":[]},{"metadata":{"trusted":false},"cell_type":"code","source":"","execution_count":null,"outputs":[]}],"metadata":{"kernelspec":{"display_name":"Python 3.8.1 64-bit ('python38': conda)","language":"python","name":"python38164bitpython38conda56991d5ad1414e06a4dcd344400cf456"}},"nbformat":4,"nbformat_minor":2}
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